(12x^2-24x-15)/20=0

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Solution for (12x^2-24x-15)/20=0 equation: 


x in (-oo:+oo)

(12*x^2-(24*x)-15)/20 = 0

(12*x^2-24*x-15)/20 = 0

12*x^2-24*x-15 = 0

3*(4*x^2-8*x-5) = 0

4*x^2-8*x-5 = 0

DELTA = (-8)^2-(-5*4*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)+8)/(2*4) or x = (8-144^(1/2))/(2*4)

x = 5/2 or x = -1/2

3*(x+1/2)*(x-5/2) = 0

(3*(x+1/2)*(x-5/2))/20 = 0

( 3 )

3 = 0

x belongs to the empty set

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x-5/2 )

x-5/2 = 0 // + 5/2

x = 5/2

x in { -1/2, 5/2 }

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